Compute unknown gas volume or temperature under constant pressure using V₁/T₁ = V₂/T₂. Visualize the linear relationship between volume and absolute temperature with an interactive graph.
Charles's Law (also known as the law of volumes) states that for a fixed amount of gas at constant pressure, the volume is directly proportional to its absolute temperature. Mathematically, V₁/T₁ = V₂/T₂. This empirical gas law was first published by Joseph Louis Gay-Lussac in 1802, but he credited the unpublished work of Jacques Charles from the 1780s. Charles discovered that oxygen, nitrogen, hydrogen, and carbon dioxide all expand equally between the same temperature interval.
V ∝ T (at constant n and P) → V/T = k
Therefore: V₁ / T₁ = V₂ / T₂
Critical: Temperature must be in Kelvin (K) – absolute scale. Using Celsius or Fahrenheit will produce incorrect results because the proportionality fails below 0°C.
From the ideal gas law PV = nRT, at constant P and n, V/T = nR/P = constant. Hence V₁/T₁ = V₂/T₂. To find V₂: V₂ = V₁ × (T₂/T₁). To find T₂: T₂ = T₁ × (V₂/V₁). The calculator automatically handles both modes and ensures temperature values > 0 K (absolute zero).
Real-world example: A balloon filled with 2.0 L of helium at 25°C (298 K) is placed in a freezer at -5°C (268 K). What is the new volume? V₂ = 2.0 L × (268/298) ≈ 1.80 L. The calculator instantly verifies this and draws the isobaric line.
| Scenario | V₁ (L) | T₁ (K) | V₂ (L) | T₂ (K) | Ratio V/T |
|---|---|---|---|---|---|
| Hot air balloon heating | 2.0 | 300 | 4.0 | 600 | 0.00667 |
| Gas cooling in a piston | 5.0 | 400 | 2.5 | 200 | 0.0125 |
| Laboratory syringe | 1.2 | 293 | 1.44 | 351.6 | 0.004096 |
| Cryogenic application | 3.0 | 273 | 1.5 | 136.5 | 0.01099 |
| Gas | Pressure (atm) | T₁ (K) | T₂ (K) | V₂ (ideal) L | V₂ (measured) L | Deviation (%) |
|---|---|---|---|---|---|---|
| Air | 1 | 300 | 600 | 4.00 | 3.98 | -0.5% |
| Helium | 1 | 300 | 600 | 4.00 | 4.01 | +0.25% |
| Carbon Dioxide | 1 | 300 | 600 | 4.00 | 3.92 | -2.0% |
| Air | 10 | 300 | 600 | 4.00 | 3.85 | -3.75% |
Pilots rely on Charles's Law to control altitude. A typical balloon envelope contains ~2500 m³ of air at 20°C (293 K). To generate lift, the burner heats the air to ~100°C (373 K). Using V₂ = V₁ × (T₂/T₁) = 2500 × (373/293) ≈ 3182 m³. The expanded hot air is less dense than the surrounding cool air, producing buoyancy. Our calculator demonstrates this critical relationship and helps pilots estimate heating requirements.
Real gas correction (van der Waals): For more accurate predictions at high pressures or low temperatures, use (P + a(n/V)²)(V - nb) = nRT. However, Charles's law remains a cornerstone for understanding gas behavior under moderate conditions.