Compute visible horizon distance using geometric optics or standard atmospheric refraction. Includes the empirical 8% rule (maritime/aviation) and the 4/3 Earth radius model (radio/engineering).
The distance to the horizon is the maximum line-of-sight distance from an observer to the apparent boundary where Earth's surface meets the sky. Due to Earth's curvature, this distance is finite and depends on observer height and atmospheric refraction. This fundamental concept is used in navigation, aviation, coastal engineering, and radio propagation.
Geometric horizon distance (ideal sphere, no atmosphere):
d = √(2Rh + h²) ≈ √(2Rh) (since h ≪ R)
where R = mean Earth radius ≈ 6371 km (3959 mi), h = observer height.
d_optical = d_geo × 1.08.
R_eff = (4/3)·R ≈ 8495 km. The radio horizon distance becomes d_radio = √(2·R_eff·h) (approximately 15% longer than geometric). This is standard in ITU recommendations and antenna design.
A lighthouse with focal plane at 50 m (164 ft) above sea level. Geometric horizon: ≈25.2 km. Using the 8% optical rule: ≈27.2 km. Using the 4/3 Earth model (for radio beacons): ≈29.1 km. The difference of nearly 4 km can be critical for ship navigation and coastal VHF radio coverage. The table below shows horizon distances for common heights.
| Observer Height | Geometric (km) | Optical 8% (km) | 4/3 Earth model (km) |
|---|---|---|---|
| 1.7 m (human eye) | 4.65 | 5.02 | 5.37 |
| 10 m (small boat) | 11.29 | 12.19 | 13.04 |
| 50 m (lighthouse) | 25.24 | 27.26 | 29.15 |
| 120 m (drone) | 39.11 | 42.24 | 45.18 |
| 10 km (airliner) | 357.1 | 385.7 | 412.5 |
In nautical astronomy, the dip of the horizon is the vertical angle between the horizontal plane at the observer and the apparent horizon. It is given by θ (arcminutes) ≈ 0.97 × √h(feet) or θ (arcminutes) ≈ 1.76 × √h(meters). This correction is essential when measuring the altitude of stars or the sun with a sextant. The dip is negative (below the horizontal) and increases with observer height. Example: For h = 10 m, dip ≈ 5.57 arcminutes.