Evaluate integrals with infinite limits or unbounded integrands. Step‑by‑step symbolic solution and convergence analysis.
An improper integral occurs when the interval of integration is infinite or the integrand has an infinite discontinuity within the interval. Convergence means the area under the curve approaches a finite number.
\[ \int_a^\infty f(x)\,dx = \lim_{t\to\infty}\int_a^t f(x)\,dx \]
\[ \int_{-\infty}^b f(x)\,dx = \lim_{t\to-\infty}\int_t^b f(x)\,dx \]
\[ \int_{-\infty}^\infty f(x)\,dx = \int_{-\infty}^c f(x)\,dx + \int_c^\infty f(x)\,dx \] (both parts must converge)
If f has a vertical asymptote at x = c (a ≤ c ≤ b):
\[ \int_a^b f(x)\,dx = \lim_{t\to c^-}\int_a^t f(x)\,dx + \lim_{t\to c^+}\int_t^b f(x)\,dx \]
Note: This calculator only checks for discontinuities at the bounds a and b. For interior singularities (e.g., ∫₋₁¹ 1/x² dx), you must split the integral manually.
| Integral form | Convergence condition | Divergence condition |
|---|---|---|
| ∫₁^∞ 1/xp dx | p > 1 | p ≤ 1 |
| ∫₀¹ 1/xp dx | p < 1 | p ≥ 1 |
| ∫₀^∞ e-ax dx (a>0) | always converges to 1/a | – |
| ∫₂^∞ 1/(x (ln x)p) dx | p > 1 | p ≤ 1 |
Identify the type: Are limits infinite? Does the integrand blow up at an endpoint or inside?
Find antiderivative F(x) using symbolic integration.
Replace improper limits with limits: e.g., limt→∞ F(t) – F(a) for infinite upper bound.
Evaluate the limits. If both one‑sided limits exist and are finite, the integral converges; otherwise it diverges.
Calculator features (updated):
inf, -inf and endpoint singularities
inf or ∞ for +∞, and -inf or -∞ for −∞. The calculator will treat them as limits.
inf for ∞, -inf for −∞
2*x not 2x
e^x use exp(x)
log(x) is natural log