Differentiate products of two functions using the product rule: (u·v)' = u'·v + u·v'. Step‑by‑step breakdown and graphical visualization.
The product rule is a formula used to find the derivative of the product of two functions. It states:
(f·g)'(x) = f'(x)·g(x) + f(x)·g'(x)
Starting from the limit definition of the derivative:
(f·g)'(x) = limh→0 [f(x+h)g(x+h) - f(x)g(x)] / h
Add and subtract f(x+h)g(x) in the numerator:
= limh→0 [f(x+h)g(x+h) - f(x+h)g(x) + f(x+h)g(x) - f(x)g(x)] / h
= limh→0 f(x+h)·[g(x+h)-g(x)]/h + limh→0 [f(x+h)-f(x)]/h · g(x)
Assuming f and g are differentiable, we obtain f(x)g'(x) + f'(x)g(x).
Think of u·v as the area of a rectangle with sides u and v. A small change dx changes u by du and v by dv. The new area is (u+du)(v+dv) = uv + u·dv + v·du + du·dv. The change in area (the derivative) is u·dv + v·du, ignoring the second‑order term du·dv. This is exactly the product rule.
| u(x) | v(x) | Product derivative (simplified) |
|---|---|---|
| x² | sin x | 2x sin x + x² cos x |
| eˣ | cos x | eˣ(cos x - sin x) |
| ln x | x³ | 3x² ln x + x² |
| sin x | cos x | cos²x - sin²x = cos 2x |
| x | eˣ | eˣ(x + 1) |
For three functions f, g, h, the product rule becomes:
(fgh)' = f'gh + fg'h + fgh'
This pattern continues for any number of factors: the derivative is the sum of the derivative of each factor times the product of the remaining factors.
The quotient rule can be derived by writing f/g = f·(1/g) and applying the product rule together with the chain rule:
(f/g)' = f'·(1/g) + f·(-1/g²)·g' = (f'g - fg')/g².
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