Compute mechanical advantage, effort force, rope tension, and displacement for fixed, movable, and compound pulley systems. Visualize rope segments, force directions, and system geometry on an interactive canvas.
A pulley system is a simple machine that uses a grooved wheel and a rope, cable, or belt to transmit force and motion. By distributing the load across multiple rope segments, pulleys provide mechanical advantage — allowing a smaller effort force to lift a heavier load. The core principle is rooted in Newtonian mechanics and the conservation of energy: the work done by the effort force equals the work done on the load (neglecting friction).
For an ideal pulley system with n rope segments supporting the load:
Mechanical Advantage (MA) = n
Effort Force (F) = W / n (ideal, no friction)
With efficiency η: F = W / (n · η) and MA = n · η
A single pulley mounted to a fixed support. It changes the direction of the applied force but provides no mechanical advantage (MA = 1). Used in flagpoles, well buckets, and simple hoists.
A pulley that moves with the load. The rope is fixed at one end, passes through the movable pulley, and is pulled at the other end. Provides MA = 2 (ideal). Reduces the required effort by half.
Combines fixed and movable pulleys (block and tackle). MA equals the number of rope segments supporting the load. Used in cranes, elevators, and sailing rigs for heavy lifting.
The calculator solves the fundamental pulley equations using the following steps:
All calculations are based on first principles of statics and energy conservation, verified against standard engineering mechanics textbooks (Beer & Johnston, Hibbeler).
Equilibrium of forces for a load supported by n rope segments:
W = n · T (ideal, no friction)
where T is the tension in each segment. The effort force F equals the tension in the pulling segment: F = T.
Thus: F = W / n → MA = W / F = n.
With efficiency η (0 < η ≤ 1): F = W / (n · η) and MA = n · η.
The rope displacement relation comes from the principle of virtual work:
F · drope = W · dload → drope = (W / F) · dload = n · dload (ideal).
With friction, the input work must also overcome losses, but the displacement ratio remains n. Efficiency does not change the geometric relationship.
| Configuration | Rope Segments (n) | Ideal MA | Effort Force (W=1000N, η=0.92) | Rope Pull / Load Displacement |
|---|---|---|---|---|
| Fixed Pulley | 1 | 1.00 | 1000 N | 1 : 1 |
| Movable Pulley | 2 | 2.00 | 543 N | 2 : 1 |
| 2‑Pulley Block | 2 | 2.00 | 543 N | 2 : 1 |
| 3‑Pulley Block | 3 | 3.00 | 362 N | 3 : 1 |
| 4‑Pulley Block | 4 | 4.00 | 272 N | 4 : 1 |
| 6‑Pulley Block | 6 | 6.00 | 181 N | 6 : 1 |
| 8‑Pulley Block | 8 | 8.00 | 136 N | 8 : 1 |
A construction crew needs to lift 1200 kg of concrete blocks (≈ 11,772 N) to the 4th floor using a temporary hoist. They have a block and tackle with 4 rope segments (n = 4) and pulleys with an estimated efficiency of 0.88.
Calculation: MA = 4 × 0.88 = 3.52. Required effort F = 11,772 / 3.52 ≈ 3,344 N (≈ 341 kg-force). The rope must be pulled 4 × 1.5 m = 6.0 m to lift the load 1.5 m. The crew can use a hand winch or an electric hoist with a capacity of at least 4 kN.
Key insight: The mechanical advantage reduces the required effort, but the operator must pull a longer length of rope — a classic trade‑off in simple machines. This calculator helps size the rope, winch, and structural supports accurately.
On a sailboat, a 3‑pulley block and tackle (n = 3) is used to tension the mainsail halyard. The sail exerts a load of 2500 N. With efficiency η = 0.85 (due to friction in the sheaves and line stiffness), the required effort is F = 2500 / (3 × 0.85) = 980 N. The sailor must pull 3 meters of line for every 1 meter of sail rise. The calculator confirms that a winch with a 1000 N capacity is suitable.