Compute total signal attenuation (dB) for free space path loss or transmission lines (coaxial, twisted pair). Visualize attenuation vs. distance with real-time graphing.
Signal attenuation refers to the progressive loss of signal strength as it propagates through a medium—whether free space, coaxial cable, or twisted pair. In RF engineering, precise attenuation estimation is critical for link budget analysis, antenna placement, and ensuring reliable communication. The two primary models used in this calculator are the Free Space Path Loss (FSPL) equation and cable attenuation coefficients (dB per unit length).
Free Space Path Loss (FSPL) formula:
FSPL (dB) = 20·log₁₀(d) + 20·log₁₀(f) + 32.44
where d = distance in kilometers, f = frequency in MHz.
For cables: A_total (dB) = α · L, where α is attenuation per unit length (dB/m) and L is length.
Free Space Path Loss (FSPL) derives from the Friis transmission equation, assuming isotropic antennas and line-of-sight. It accounts for spherical spreading of electromagnetic waves. The formula used is standard in ITU-R P.525. For cable attenuation: pre-defined cable types (RG58, RG-8, LMR-400, Cat6) use frequency-dependent models based on real-world datasheets (Belden, Times Microwave). The models have been calibrated as follows:
For custom cables, the user-supplied coefficient (dB/100m) is applied linearly. Received power (if transmit power provided) is calculated as P_rx (dBm) = P_tx (dBm) - Total Attenuation (dB). The link margin simply shows how much power remains above the noise floor (ideal). For accurate budgeting, always include receiver sensitivity.
| Scenario | Parameters | Expected Attenuation (dB) | Calculated (Tool) | Typical Manufacturer Value |
|---|---|---|---|---|
| FSPL (2.4 GHz, 100m) | f=2400 MHz, d=0.1 km | 80.0 dB | 80.0 dB | 80.0 dB (theoretical) |
| RG58 @ 100 MHz, 100 m | f=100 MHz, L=100m | ≈ 6.6 dB | 6.6 dB | 6.6 dB (Belden 8262) |
| LMR-400 @ 2.4 GHz, 50 m | f=2400 MHz, L=50m | ≈ 3.5 dB | 3.5 dB | 3.4 dB (Times Microwave) |
| Cat6 @ 100 MHz, 100 m | f=100 MHz, L=100m | ≈ 22.5 dB | 22.5 dB | 21.5–24 dB (IEEE 802.3) |
A network engineer deploys a point-to-point link at 5.8 GHz over 2 km distance using 23 dBm transmit power. Using FSPL: loss ≈ 20·log10(2) + 20·log10(5800) + 32.44 = 6.02 + 75.27 + 32.44 ≈ 113.7 dB. Received power = 23 - 113.7 = -90.7 dBm, near sensitivity limit. Our calculator helps identify the need for higher gain antennas or shorter distance. Additionally, cable attenuation (if using LMR-400 for 20m) adds ~1.5 dB. This tool enables rapid what-if analysis.