Quantify the heat storage capacity of any material or building element using the fundamental thermodynamics equation Q = m · c · ΔT. Evaluate thermal inertia, optimize passive solar gains, reduce HVAC loads, and design energy‑resilient buildings.
Thermal mass is the ability of a material to absorb, store, and release heat energy. It is quantified by the heat capacity equation Q = m · c · ΔT, where Q is stored energy (joules), m is mass (kg), c is specific heat capacity (J/(kg·K)), and ΔT is the temperature swing. In buildings, high thermal mass (e.g., concrete, brick, stone, water) moderates indoor temperatures by absorbing excess heat during the day and releasing it at night, reducing peak HVAC loads and improving thermal comfort.
Fundamental Heat Storage Equation:
Q [kWh] = (m [kg] × c [kJ/(kg·K)] × ΔT [K]) / 3600
Where 1 kWh = 3.6 × 10⁶ J. The thermal mass effect directly influences building energy performance and passive solar strategies.
1. Define system: Determine the building component (slab, wall, water tank) and its total mass.
2. Select material: Each material has a specific heat capacity (c). Concrete ~880 J/(kg·K); water has extremely high c = 4186 J/(kg·K) → excellent for thermal batteries.
3. Estimate ΔT: In passive design, typical daily indoor temperature swing is 6–12 K depending on climate and ventilation.
4. Compute Q: Using Q = m·c·ΔT. Convert to kWh (divide by 3.6e6).
5. Interpret: A result > 5 kWh per 10 m² of floor area indicates significant storage potential, capable of covering overnight heating/cooling needs.
| Material | Density (kg/m³) | Specific Heat c (J/(kg·K)) | Volumetric Heat Capacity (kJ/(m³·K)) | Typical Application |
|---|---|---|---|---|
| Reinforced Concrete | 2400 | 880 | 2112 | Slabs, foundations, walls |
| Clay Brick | 1600 | 840 | 1344 | Masonry walls |
| Timber (Oak) | 700 | 1200 | 840 | Lightweight construction |
| Water | 1000 | 4186 | 4186 | Thermal storage tanks, hydronic systems |
| Phase Change Material (PCM) | 850 | 2000 (solid/liquid) + latent heat | ~1700 + latent ~200 kJ/kg | Advanced peak load shifting |
| Steel | 7850 | 490 | 3846 | Structural elements (fast response) |
A 200 m² office floor in Zurich uses a 250 mm concrete slab (mass = 200 m² × 0.25 m × 2400 kg/m³ = 120,000 kg). Specific heat = 880 J/(kg·K). Night ventilation cools the slab from 26°C to 18°C (ΔT = 8 K). Stored heat released during occupied hours: Q = 120,000 × 880 × 8 = 844.8 MJ ≈ 235 kWh. This covers ~70% of daytime cooling load, reducing chiller energy by 40% annually. The calculator reproduces these savings and supports LEED / Passive House certification.
While insulation resists heat flow (low U-value), thermal mass stores heat. The combination creates high-performance envelopes: insulation keeps heat in/out, while thermal mass smooths temperature spikes. In Mediterranean climates, external insulation + internal exposed mass reduces cooling energy by up to 50%. Our calculator helps engineers size the mass needed for a given ΔT and desired storage capacity.
PCMs store 5–14 times more energy per unit mass than concrete by utilizing latent heat. For example, paraffin wax with melting point 23°C absorbs 200 kJ/kg during phase change. Our material library includes a PCM option (using effective specific heat including latent contribution for simplified modeling). For detailed dynamic simulation, refer to ISO 13786.
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Page Last Reviewed: April 2026. Content is periodically updated to reflect current standards.
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Q = m·c·ΔT) is implemented in JavaScript and independently verified against manual calculations and spreadsheet models.
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