Solve any constant-acceleration motion problem. Compute displacement using three classic SUVAT modes: initial velocity + acceleration + time, initial + final velocity + time, or initial + final velocity + acceleration.
The displacement calculator applies the fundamental kinematic equations (SUVAT) that govern motion with constant acceleration. These equations are pillars of classical mechanics, used universally in physics education, engineering design, and real‑world trajectory analysis. Our interactive velocity‑time graph provides an intuitive grasp of how displacement equals the signed area under the v‑t curve — a direct visualization of integration at work.
s = displacement u = initial velocity v = final velocity a = acceleration t = time
(1) s = ut + ½at² (2) s = ½(u+v)t (3) v² = u² + 2as
For constant acceleration a, velocity changes linearly: v(t) = u + a t. The displacement is the integral of velocity over time: s = ∫₀ᵗ (u + aτ) dτ = u t + ½ a t². This is mode 1. Mode 2 uses the average velocity: s = ((u+v)/2)·t, which is exact for uniform acceleration. Mode 3 derives from v² = u² + 2as ⇒ s = (v² − u²)/(2a), provided a ≠ 0. Our algorithm solves the linear system or directly applies the corresponding equation, then calculates secondary quantities (average velocity, final velocity, etc.).
A car travels at 28 m/s (~100 km/h). The driver sees an obstacle and applies brakes, decelerating at –6 m/s². Using mode 3 (u=28, v=0, a=-6), the displacement calculator yields s = (0² − 28²)/(2×−6) = 65.33 m. This stopping distance is critical for civil engineers designing safe following distances. The v‑t graph shows a linear decrease, and the triangular area under the curve matches the computed displacement. The tool also reveals braking time t = (v−u)/a ≈ 4.67 s. Such analyses are used in accident reconstruction and autonomous vehicle emergency systems.
| Scenario | Mode | Input values | Displacement | Interpretation |
|---|---|---|---|---|
| Free fall from rest | 1 (u,a,t) | u=0, a=9.8, t=3 s | 44.1 m | Vertical drop distance (ignoring air drag) |
| Train acceleration | 2 (u,v,t) | u=5, v=25, t=20 s | 300 m | Station platform to cruise speed |
| Projectile ascent | 3 (u,v,a) | u=30, v=0, a=-9.8 | 45.92 m | Maximum height |
| Constant velocity | 1 (u,a,t) | u=12, a=0, t=8 s | 96 m | Uniform motion: s = ut |
Galileo's studies on inclined planes used time‑distance relationships; modern physics visualizes motion through velocity‑time diagrams. The slope gives acceleration, and the area under the curve (shaded in the interactive canvas) equals displacement. This geometric connection makes abstract calculus tangible — a cornerstone of Newtonian mechanics. Our tool automatically scales axes, highlights the region, and reinforces the relationship between the algebraic SUVAT equations and their graphical representation.