Compute exact instantaneous velocity v(t) from polynomial position function s(t). Visualize the position-time curve, tangent slope, and step-by-step derivative using analytic differentiation.
Instantaneous velocity describes how fast an object moves at an exact moment in time. Unlike average velocity over an interval, instantaneous velocity is the limit of the average velocity as the time interval approaches zero: v(t) = limΔt→0 (Δs/Δt) = ds/dt. In calculus, it is the first derivative of the position function s(t) with respect to time. This tool calculates the exact derivative for polynomial position functions and draws the corresponding tangent line, giving you a visual intuition of the slope at any point.
If s(t) = a t³ + b t² + c t + d, then
v(t) = 3a t² + 2b t + c (derivative power rule)
Given the polynomial s(t) = a t³ + b t² + c t + d, the power rule of differentiation yields v(t) = 3a t² + 2b t + c. The second derivative (acceleration) becomes a(t) = 6a t + 2b, which is linear if a ≠ 0. For quadratic motion (a=0), acceleration is constant = 2b. Our calculator performs analytic differentiation, guaranteeing exact results (no numeric approximation errors). The interactive graph samples position values for t ∈ [t_min, t_max] (adaptive range around your chosen t) and draws the curve using 200 points, then overlays the tangent line computed from the derivative at that exact point.
For non-polynomial scenarios, this tool focuses on polynomials because they represent the majority of introductory physics and calculus problems (free fall, spring motion, basic kinematics). The accuracy is limited only by floating-point precision (≈ 15 significant digits).
| Scenario | Position function s(t) | Time t | Instantaneous velocity | Interpretation |
|---|---|---|---|---|
| Free fall (near Earth) | 4.9 t² | 2.0 s | 19.6 m/s | Downward speed increases linearly |
| Constant velocity car | 5 t | 3.0 s | 5.0 m/s | Steady motion, no acceleration |
| Quadratic acceleration | 2t² + 3t | 1.5 s | 9.0 m/s | Velocity increases due to linear acceleration |
| Cubic jerk motion | t³ - 2t² + t | 1.0 s | 0.0 m/s | Instantaneous rest (direction change) |
| Projectile upward | -4.9t² + 20t | 1.0 s | 10.2 m/s | Object still rising but slowing |
A vehicle’s position during braking is modeled as s(t) = -2t³ + 12t² + 10t (meters) from t=0 to t=4 seconds. Using our calculator (a=-2, b=12, c=10, d=0), at t=1.5 s, instantaneous velocity v = 3*(-2)*(1.5)² + 2*12*1.5 + 10 = -13.5 + 36 + 10 = 32.5 m/s. By t=3 s, v drops to -2*27 + 72 + 10 = -54+82=28 m/s. The graph helps safety engineers visualize deceleration before full stop. The point where v=0 indicates the moment the vehicle stops, crucial for accident reconstruction.