Pump Power Calculator

Accurately compute pump hydraulic power (kW) and required shaft power (kW) based on flow rate, head, fluid density, and pump efficiency. Ideal for centrifugal pump selection, energy audits, and system design.

Water = 1000, Oil ≈ 850
Gravity constant g = 9.81 m/s² (fixed). Hydraulic power = ρ·g·Q·H / 1000 (kW). Shaft power = Hydraulic / (η/100).
Quick examples:
? Water transfer (100 m³/h, 30 m, 75%)
⛰️ High head (50 m³/h, 80 m, 68%)
?️ Light oil (ρ=850, 40 m³/h, 25 m, 70%)
⚙️ Slurry pump (120 m³/h, 18 m, 62%)
? Clean water booster (200 m³/h, 45 m, 82%)
All calculations performed locally. No data uploaded. Transparent engineering formulas.
Power comparison: Hydraulic vs Shaft
Hydraulic power (kW)
Shaft power (kW)
Bar heights relative to maximum of both powers. Shaft power ≥ Hydraulic power.

Understanding Pump Power: Engineering Fundamentals

The hydraulic power (Phyd) represents the energy transferred to the fluid per unit time, while the shaft power (Pshaft) is the mechanical power input at the pump shaft. The difference is due to pump efficiency (η), which accounts for hydraulic, volumetric, and mechanical losses. Accurate power calculation is essential for motor sizing, energy consumption forecasts, and system optimization.

? Fundamental formulas (metric system):
Phyd = (ρ × g × Q × H) / 1000 [kW]
Pshaft = Phyd / (η/100) [kW]
where ρ = density (kg/m³), g = 9.81 m/s², Q = flow rate (m³/s), H = head (m), η = efficiency (%).

These equations derive from the Bernoulli principle and are standardised by the Hydraulic Institute (HI) and ISO 9906. Proper pump sizing reduces energy waste — a 5% efficiency increase can save thousands of kWh annually in industrial settings.

Real‑World Industrial Applications

Case Study: Wastewater Treatment Plant

A municipal plant operates a centrifugal pump at Q = 320 m³/h, H = 12 m, ρ = 1020 kg/m³, η = 68%. Using our calculator, Phyd = (1020×9.81×0.0889×12)/1000 ≈ 10.67 kW, Pshaft ≈ 15.69 kW. After impeller trimming and η improvement to 74%, the shaft power dropped to 14.42 kW, saving over 11,000 kWh/year. This tool provides immediate insight into energy efficiency measures.

Case Study: Irrigation Pump Selection

An agricultural project needs Q = 150 m³/h, H = 45 m, water density. With η = 72%, required shaft power = 25.5 kW. The nearest standard motor is 30 kW. The calculator’s motor power estimate includes 10% service factor, ensuring reliable operation under voltage variations.

Step‑by‑Step Calculation Process

  1. Enter flow rate and select unit (m³/h, L/s or m³/s).
  2. Specify total dynamic head (TDH) in meters.
  3. Define fluid density (default 1000 kg/m³ for water).
  4. Provide pump efficiency (typical centrifugal: 55% to 85%).
  5. Click “Calculate Power” — instant results, including converted flow rate and recommended motor power.

Pump Efficiency Reference Table

Pump type Typical efficiency range Notes
Centrifugal (large, >100 kW) 75% – 88% High flow, low viscosity
Centrifugal (small, <10 kW) 50% – 70% Domestic or light industrial
Positive displacement 65% – 85% Steady flow regardless of pressure
Slurry / Abrasive pumps 45% – 65% Wear reduces efficiency
Submersible pumps 55% – 75% Motor cooling integrated

Critical Factors Affecting Pump Power

  • Viscosity: Higher viscosity increases friction losses → efficiency drop; our calculator uses density correction but for viscous fluids consult additional charts.
  • Operating point: Running far from BEP (best efficiency point) causes excessive power draw.
  • Altitude & NPSH: Low atmospheric pressure may require reduced shaft speed; however hydraulic power formula remains valid.
  • Wear & tear: Impeller erosion reduces efficiency over time, increasing shaft power for same duty.

? Engineering source integrity — formulas adhere to the Hydraulic Institute Standards and ANSI/HI 1.3-2021. Validation performed against industrial pump curves from Grundfos and Goulds. Last updated: May 2026. Free tool for non‑commercial & professional use.

Frequently Asked Questions (FAQ)

Shaft power includes all internal losses (bearings, leakage, recirculation, disk friction). Hydraulic power is the ideal fluid power; efficiency η < 1 means shaft power > hydraulic power.

Yes, simply adjust the density (kg/m³). For non-Newtonian or extremely viscous fluids, efficiency may deviate — consult manufacturer data.

We added a 1.1 factor (10% margin) for motor power estimate; it's a safe practice for continuous duty pumps.

Using flow meter and pressure gauges: η = (ρ·g·Q·H)/(P_motor × η_motor). This tool helps back-calculate if power draw is known.
References: Hydraulic Institute, Engineering ToolBox, “Centrifugal Pump Handbook” by Sulzer.