Compute ultimate shear and bearing capacity for riveted joints according to ASME, MIL-HDBK-5, and Eurocode 3. Evaluate single/double shear configurations, visualize load transfer, and get safe design recommendations.
Riveted joints remain essential in aircraft fuselage, steel bridges, cranes, and heavy machinery. The total joint strength is governed by two independent failure mechanisms: shear failure of the rivet(s) and bearing (crushing) failure of the plate or rivet hole. This calculator implements ultimate strength design per MIL-HDBK-5J and ASME B&PV Code Section VIII.
Shear capacity (single shear): Ps = n × (π·d²/4) · τu / 1000 [kN]
Shear capacity (double shear): Ps = n × 2 × (π·d²/4) · τu / 1000 [kN]
Bearing capacity: Pb = n × (d · t) · σb / 1000 [kN]
Joint Capacity: Pjoint = min(Ps, Pb)
Where d = rivet diameter (mm), t = thickness of the thinnest connected plate (mm), τu = ultimate shear strength of rivet material (MPa), σb = ultimate bearing strength of plate material (MPa). For multi‑rivet joints, capacity scales linearly with number of rivets provided spacing meets code requirements (edge distance ≥ 2d, pitch ≥ 3d).
1. Compute rivet cross‑sectional area A = π·d²/4 (mm²).
2. For single shear, shear force per rivet = A·τu (N). Multiply by number of rivets, convert to kN.
3. For double shear, effective shear area doubles: Ps,double = 2·A·τu per rivet.
4. Bearing capacity per rivet = d·t·σb (N).
5. The controlling failure mode is the lower value; if shear < bearing → rivet shear governs; else bearing failure of plate.
6. If applied load is provided, safety factor = total capacity / applied load. A safety factor ≥ 1.5 is typical for static applications (ultimate load). For cyclic loads, higher factors are recommended.
| Standard | Application | Recommended Safety Factor (Ultimate) |
|---|---|---|
| MIL-HDBK-5J (Metallic Materials) | Aerospace rivets (MS, NAS) | 1.5 – 2.0 |
| ASME B&PV Sec. VIII | Pressure vessel riveting | 4.0 (against yield) |
| Eurocode 3 (EN 1993-1-8) | Steel structures | 1.25 – 1.35 |
| ISO 14588 & ISO 15977 | Blind rivets & structural rivets | ≥ 2.0 |
In a typical aluminium airframe, a lap joint uses 4.8 mm diameter rivets (2117-T4 rivets, τu ≈ 240 MPa) with skin thickness 1.6 mm (2024-T3, σb ≈ 380 MPa). For a single-shear joint with 12 rivets, our calculator gives shear capacity = 12 × (π·4.8²/4×240/1000) ≈ 12 × 4.34 kN = 52.08 kN; bearing capacity = 12 × (4.8×1.6×380/1000) = 12 × 2.92 kN = 35.04 kN → joint limited by bearing. The engineer would increase rivet pitch or use thicker skin. This analysis matches typical FAA repair guidelines.