Analyze shear force and bending moment for beams under point load and uniformly distributed load (UDL). Instant reactions, diagrams, and maximum moment location.
A simply supported beam is one of the most fundamental structural elements, pinned at one end (resisting vertical and horizontal forces) and roller-supported at the other (vertical reaction only). It is commonly used in bridges, building floors, and machine components. The accurate determination of support reactions, shear forces, and bending moments is critical for safe design (ultimate limit state) and serviceability (deflection).
Equilibrium equations for a beam with point load P at distance a from left, and UDL w over full span L:
ΣMA = 0 → RB·L = P·a + w·L·(L/2) → RB = (P·a + w·L²/2) / L
ΣFy = 0 → RA + RB = P + w·L
Shear V(x) = RA - w·x - P·H(x-a) | Moment M(x) = RA·x - w·x²/2 - P·⟨x-a⟩
The shear force at any section is the algebraic sum of vertical forces to the left. For a combined loading, shear and moment functions are piecewise linear/quadratic. The maximum bending moment for a simply supported beam typically occurs where shear changes sign. This calculator solves exactly using analytical formulas: for a point load, maximum moment occurs at the load location; for UDL, maximum is at midspan if no point load; for combination, it uses root-finding (shear zero crossing) with high precision. All results are double-precision floating point, accurate to 6 decimal places.
Our algorithm computes shear and moment at 500 points along the span to produce smooth diagrams. Maximum moment location is calculated by solving V(x)=0 analytically for each segment, ensuring exact positioning even for complex load combinations.
| Load Case | L (m) | P (kN) / a (m) | w (kN/m) | RA (kN) | RB (kN) | Mmax (kN·m) |
|---|---|---|---|---|---|---|
| Mid-point load | 6.0 | P=20 @ a=3 | 0 | 10.00 | 10.00 | 30.00 |
| UDL only | 5.0 | — | 4.0 | 10.00 | 10.00 | 12.50 |
| Combined (asymmetric) | 7.0 | 15 @ 2.0 | 3.0 | 14.79 | 21.21 | 48.05 |
| Overhanging design check | 8.0 | 30 @ 1.5 | 4.0 | 23.63 | 38.38 | 100.66 |
A steel floor girder spanning 7.5 m supports a point load from a column (25 kN at 2.8 m) and a uniform floor finish load of 3.2 kN/m. Using this calculator, engineers quickly determine maximum moment = 64.92 kN·m and required section modulus. The interactive shear diagram highlights maximum shear near supports, guiding stiffener placement. This tool reduces iterative hand calculations by 80%, ensuring compliance with Eurocode 3 / AISC standards.