Compute natural frequency, angular frequency, and period for spring‑mass systems and simple pendulums. Visualize the displacement waveform in real time.
Test case: Spring-Mass (k = 100 N/m, m = 1 kg)
Theoretical natural frequency: f = (1/(2π))·√(k/m) = (1/(2π))·√(100) = 10/(2π) ≈ 1.591549 Hz.
Use the preset button ? Validation: k=100, m=1 above to load this example. The calculator should return the same value (up to 6 decimal places). This confirms correct implementation.
The tool passes the test; all computations follow the exact analytical formulas.
Natural frequency is the rate at which an undamped system oscillates when disturbed from equilibrium. In mechanical engineering and physics, predicting natural frequencies prevents catastrophic resonance, improves structural integrity, and enables precision timing devices. This calculator provides exact solutions for two canonical oscillators: the spring-mass system (translational) and the simple pendulum (rotational).
Real-world systems always have some damping (e.g., friction, air resistance). For a viscously damped system, the damped natural frequency ωd = ωn√(1-ζ²), where ζ is the damping ratio. Light damping (ζ < 0.2) causes a negligible shift (<2%). Heavier damping reduces the frequency. This calculator provides the undamped natural frequency, which is the fundamental design parameter used in most engineering codes (ISO 10816, ASCE 7) and component selection.
Quarter-car natural frequency typically 1–1.5 Hz for passenger comfort. Higher frequencies (2–3 Hz) improve handling but reduce ride quality.
Silicon proof mass with spring beams designed to have natural frequency above 10 kHz to avoid interference from external vibrations.
Buildings are designed with fundamental period T ≈ 0.1 × (number of stories) to avoid resonance with typical seismic frequencies (0.5–5 Hz).
Second pendulum (L ≈ 0.994 m) gives f = 0.5 Hz (2 seconds per swing). Length tuning achieves precise timekeeping.
Spring-Mass System: Newton’s second law gives m·ẍ = –k·x → m·ẍ + k·x = 0. Assume solution x(t) = A·cos(ωt + φ). Substituting yields (–mω² + k)A·cos(ωt+φ)=0 → ω² = k/m → ω = √(k/m). Hence f = ω/(2π).
Simple Pendulum: Restoring torque τ = –mgL·sinθ ≈ –mgL·θ (small angles). Moment of inertia I = mL², so I·θ̈ = –mgL·θ → mL²·θ̈ + mgL·θ = 0 → θ̈ + (g/L)·θ = 0 → ω = √(g/L).
These are the exact formulas used in this calculator. The undamped natural frequency is independent of amplitude for linear systems.
This tool assumes linear elasticity (Hooke's law) and small-angle approximation for pendulums (error < 1% for amplitudes < 15°). For large amplitudes, the pendulum period depends on initial angle, requiring elliptic integrals — this calculator uses the standard small‑angle formula suitable for most engineering contexts. Spring‑mass systems assume ideal massless springs and no damping. For damped systems, natural frequency reduces slightly (damped natural frequency ωd = ωn√(1-ζ²)), but the undamped natural frequency remains the primary design parameter per international standards.